In English
Suomeksiuusisivu13
joojee
jeejeejee
video
\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)
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uusisivu13
joojeejeejeejee
video
\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\) |
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